#include <bits/stdc++.h>
using namespace std;
signed main() {
ios::sync_with_stdio(0);
int n;
cin>>n;
vector<int> a(n,0);//数组a初始化为0
for(int i=0;i<n;++i){
cin>>a[i];
}
sort(a.begin(),a.end());
for(auto &i:a)cout<<i<<" \n"[&i==&a.back()];//空格的控制
return 0;
}
1.2全排列函数next_permutation(a, a + n)
#include <bits/stdc++.h>
using namespace std;
vector<int> V;
int main()
{
int n = 4;
int a[4] = {1, 2, 3, 4};
do
{
for (int i = 0; i < 4; i++)
{
printf("%d%c", a[i], i == 3 ? '\n' : ' ');
}
} while (next_permutation(a, a + n));
return 0;
}
思想:异或操作
class Solution {
public:
int missingNumber(vector<int>& nums) {
int ans=nums.size();
for(int i=0;i<nums.size();i++){
ans^=i;
ans^=nums[i];
}
return ans;
}
};
#include <iostream>
using namespace std;
int main()
{
// 请在此输入您的代码
int n;
cin>>n;
string a;string b;
cin>>a;
cin>>b;
int a0=0,a1=0,b0=0,b1=0;
for(int i=0,len1=a.size();i<len1;i++)
{
if(a[i]=='1'){a1++;}
else a0++;
}
for(int j=0,len2=b.size();j<len2;j++){
if(b[j]=='1'){b1++;}
else b0++;
}
int sum=min(a0,b1)+min(a1,b0);
cout<<sum;
return 0;
}